solve it pls !! ans soon
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Eq. Has equal roots.. --> D=0 b^2 - 4ac = 0 (2k - 10)^2 - 4(k-5)(2) = 0 4k^2 +100 - 40k - 8k +40 = 0 (4k^2 -48k +140= 0) ÷ 4 K^2 - 12k + 35 =0 K^2 -7k - 5k +35 =0 K(k-7) -5(k -7)=0 (K-7)(k-5) =0 K = 7 or k = 5.. #hope it helps.
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