Question

solve it pls hlp me ....​

Answer 1

Given :-

A balloon is connected to a meteorological ground station by a cable of length 215 m inclined at 60° to the horizontal.

To Find :-

Height of balloon

Solution :-

Let height of balloon = AB = x m

Now,

In ΔABC

${\boxed{\sf sin\theta=\dfrac{AB}{AC}}}$

$\sf\implies \sin(60^{\circ})=\dfrac{x}{215}$

We know that

• sin(60°) = √3/2

$\sf\implies \dfrac{\sqrt{3}}{2}=\dfrac{x}{215}$

$\sf\implies 215\times\sqrt{3}=2\times x$

$\sf\implies 215\sqrt{3}=2x$

$\sf\implies \dfrac{215\sqrt{3}}{2}=x$

$\sf\implies 107.5\sqrt{3}=x$

Therefore,

Height of balloon from the ground is 107.5√3 m