Question

Solve it plsssss........................

The base of a triangle is 9 cm and height is 5 cm. The base of another triangle is 10 cm and height is 6 cm. Find the ratio of areas of these triangles.

Answer 1

Answer:

3:4

Step-by-step explanation:

Ratio of 1st triangle:

Given, Base = 9 cm and Height = 5 cm.

Area of Δ₁ = (1/2) * b * h

                 = (1/2) * 9 * 5

                 = 45/2 cm²

Ratio of 2nd triangle:

Given, Base = 10 cm and height = 6 cm.

Area of Δ₂ = (1/2) * b * h

                 = (1/2) * 10 * 6

                 = 30 cm²

Ratio of areas of these triangles:

Δ₁/Δ₂

= (45/2)/30

= (45/60)

= 3/4

= 3 : 4

Therefore, ratio of areas of these triangles = 3:4

Hope it helps!

Answer 2

Area of triangles =
$1 \div 2 \times b \times h$
Area of triangles 1= 1/2×9×5
=45/2

Area of triangles 2 = 1/2×10×6
=60/2
=30

Ratio of the ares of triangles 1 : 2

= 45/2÷30

=45/60

=3/4

=3:4

Hope this helps you...