Solve it plsssss........................
The base of a triangle is 9 cm and height is 5 cm. The base of another triangle is 10 cm and height is 6 cm. Find the ratio of areas of these triangles.
Answers
Answered by
5
Answer:
3:4
Step-by-step explanation:
Ratio of 1st triangle:
Given, Base = 9 cm and Height = 5 cm.
Area of Δ₁ = (1/2) * b * h
= (1/2) * 9 * 5
= 45/2 cm²
Ratio of 2nd triangle:
Given, Base = 10 cm and height = 6 cm.
Area of Δ₂ = (1/2) * b * h
= (1/2) * 10 * 6
= 30 cm²
Ratio of areas of these triangles:
Δ₁/Δ₂
= (45/2)/30
= (45/60)
= 3/4
= 3 : 4
Therefore, ratio of areas of these triangles = 3:4
Hope it helps!
pappya36:
thnx
Answered by
4
Area of triangles =
Area of triangles 1= 1/2×9×5
=45/2
Area of triangles 2 = 1/2×10×6
=60/2
=30
Ratio of the ares of triangles 1 : 2
= 45/2÷30
=45/60
=3/4
=3:4
Hope this helps you...
Area of triangles 1= 1/2×9×5
=45/2
Area of triangles 2 = 1/2×10×6
=60/2
=30
Ratio of the ares of triangles 1 : 2
= 45/2÷30
=45/60
=3/4
=3:4
Hope this helps you...
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