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Explanation:
In parallel R=1/2+1/2= 1ohm
I =1.2A
permittivity = I(R+r)= 1.2(1+r) =1.2+1.2r
I=0.4A
permittivity=I(R+r)=0.4(4+r)=1.6+0.4r
It means
1.2+1.2r =1.6+0.4r
0.8r=0.4
r=0.4/0.8=1/2=0.5 ohm
permittivity=I(R+r) =1.2(1+0.5)=1.8V
Answered by
2
Answer:
Emf of the cell (e) = I(R+r)
resistance in parallel, R= 2×2÷2+2=1 ohm
resistance in series, r = 2+2=4 ohm
At first event, E=1.2(l+r)....................... (1)
At second event. E= 0.4(4+r).....................(2)
from 1 and 2 equation
0.4(4+r) = 1.2(l+r)
r=0.5 ohm
E= 0.4(4+0.5)
E=1.8V
Explanation:
hence, EMF of cell is 1.8V
internal resistance,r= 0.5 ohm
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