Solve it plzz plzz
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Answered by
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cos(3π/2+x)*cos(2π+x) [ cot(3π/2 - x) + cot(2π+x) ]
= sinx*cosx *[ tanx+cotx]
= sinxcosx ( sinx/cosx + cosx/sinx)
= sinxcosx ( (sin²x+cos²x) /sinxcosx)
= (1)
=1
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