Math, asked by chaviLOVER, 1 year ago

Solve it plzz plzz ​

Attachments:

Answers

Answered by SwaggerGabru
1

Answer:

HOPE THE ATTACHMENT HELPS YOU

Attachments:
Answered by 217him217
1

Answer:

cos(3π/2+x)*cos(2π+x) [ cot(3π/2 - x) + cot(2π+x) ]

= sinx*cosx *[ tanx+cotx]

= sinxcosx ( sinx/cosx + cosx/sinx)

= sinxcosx ( (sin²x+cos²x) /sinxcosx)

= (1)

=1

Similar questions