solve it plzzz as fast as possible
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1). d=2m then r=1m
h=20m
volume of cylinder=πr²h
since we'll is to be dug in the shape of the cylinder
volume=3.14*1*1*20=62.8m³ of soil must be taken
2). surface area=2πrh
since upper and lower part of well is open
s.a=2*3.14*1*20=125.6m²
then cost of plastering=50*125.6=₹6280
h=20m
volume of cylinder=πr²h
since we'll is to be dug in the shape of the cylinder
volume=3.14*1*1*20=62.8m³ of soil must be taken
2). surface area=2πrh
since upper and lower part of well is open
s.a=2*3.14*1*20=125.6m²
then cost of plastering=50*125.6=₹6280
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