Math, asked by arshi9248, 6 months ago

solve it plzzzz. ???!​

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Answered by BrainlyEmpire
7

{ \frak  { \underline \purple{Correct \:  Question :  - }}} \:

One angle of a parallelogram is 45° more than its adjacent angle. Find the angles of the parallelogram.

{ \frak  { \underline \purple{Required \:  Answer :  - }}} \:

{ \frak  { \underline \purple{Given :  - }}} \:

One angle of parallelogram is 45° more than its adjacent angle.

{ \frak  { \underline \purple{To \:  Find :  - }}} \:

All angles of given parallelogram.

\large\boxed{\boxed{\sf{ ⇝So\:let's \:do\:it\::-}}}

Let it's adjacent angle of given angle = x

Atq,

ㅤㅤGiven angle is 45° more than it's ㅤㅤㅤㅤadjacent angle.

∴ Given angle = x + 45°

Now,

Sum of adjacent angles of llgm = 180°

So,

ㅤx + x + 45° = 180°

ㅤ2x + 45° = 180°

ㅤ2x = 180° - 45°

ㅤ2x = 135°

ㅤx = \dfrac{135°}{2}

ㅤx = \cancel{\dfrac{135°}{2}}

ㅤx = 67.5°

∴ Adjacent angle of given angle = 67.5°

\sf{So, \:Given \:angle\: = x \:+ \:45°\: =\: 67.5°\: +\: 45° \:=\: \boxed{112.5°}}

Opposite angles of llgm are equal

∴ ∠A = ∠C = 112.5°

ㅤ∠B = ∠D = 67.5°

\huge\mathrm{\underline \green {Hence\:Solved}}

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Answered by Anonymous
0

Answer:

One angle of a parallelogram is 45° more than its adjacent angle. Find the angles of the parallelogram.

{ \frak { \underline \purple{Required \: Answer : - }}} \:

RequiredAnswer:−

{ \frak { \underline \purple{Given : - }}} \:

Given:−

One angle of parallelogram is 45° more than its adjacent angle.

{ \frak { \underline \purple{To \: Find : - }}} \:

ToFind:−

All angles of given parallelogram.

\large\boxed{\boxed{\sf{ ⇝So\:let's \:do\:it\::-}}}

⇝Solet

sdoit:−

Let it's adjacent angle of given angle = x

Atq,

ㅤㅤGiven angle is 45° more than it's ㅤㅤㅤㅤadjacent angle.

∴ Given angle = x + 45°

Now,

Sum of adjacent angles of llgm = 180°

So,

ㅤx + x + 45° = 180°

ㅤ2x + 45° = 180°

ㅤ2x = 180° - 45°

ㅤ2x = 135°

ㅤx = \dfrac{135°}{2}

2

135°

ㅤx = \cancel{\dfrac{135°}{2}}

2

135°

ㅤx = 67.5°

∴ Adjacent angle of given angle = 67.5°

\sf{So, \:Given \:angle\: = x \:+ \:45°\: =\: 67.5°\: +\: 45° \:=\: \boxed{112.5°}}So,Givenangle=x+45°=67.5°+45°=

112.5°

Opposite angles of llgm are equal

∴ ∠A = ∠C = 112.5°

ㅤ∠B = ∠D = 67.5°

\

{\underline \green {Hence\:Solved}}

______________________________________

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✩ But if you uses the app, please swipe right of the screen to see the full answer.

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