Question

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Answer 1

your answer is in above attachment

please refer it

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Answer 2

Angle: BOC and angle: Aod = 280° (both are vertically opposite angle ).

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:$Now, 280÷2 =140. (two angles are given and vertically opposite angles are equal)

Therefore, Boc=140°and Aod=140°.---eq1

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:$

Boc + Bod = 180° (linear pair angles ). Boc =140° (from eq1 ). 140°+ Bod = 180°. Bod = 180-140 Hence, Bod = 40°. –––––eq2.

$\: \: \: \: \: \: \: \: \: \: \: \: \:$

Angle Bod is vertically opposite to angle Aoc. (from given) Therefore,Bod = Aoc---eq3 Hence, angle Aoc = 40°

$\: \: \: \: \: \: \: \: \: \: \: \: \:$

Therefore : Aoc=40°. Bod=40°. Boc = 140 °. Aod = 140°

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