Solve it plzzzzzzzzzzzzzz
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Step-by-step explanation:
The equation has has equal roots, then
(b) ^2-4ac=0
(-2k) ^2-4(1) (7k-12) =0
4(k)^2-28k+48=0
(k) ^2-7k+12=0
(k-3) (k-4) =0
k=3, 4
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