Question

Solve it plzzzzzzzzzzzzzz

Answer 1

Answer:

Step-by-step explanation:

The equation has has equal roots, then

(b) ^2-4ac=0

(-2k) ^2-4(1) (7k-12) =0

4(k)^2-28k+48=0

(k) ^2-7k+12=0

(k-3) (k-4) =0

k=3, 4