Question

Solve it. Praveen wanted to make a temporary shelter for her car, by making a box-like structure with tarpaulin that covers all the four sides and the top of the car ( which is the front face as a flap which can be rolled up). Assuming that the stitching margins are very small, and therefore negligible, how much tarpaulin would be required to make the shelter of height 2.5m, with base dimensions 4m×3m?​

Answer 1

Answer:

47 m^2

Step-by-step explanation:

the surface area of cuboid except bottom is 47 m^2

Answer 2

$\huge \underline \mathbb {SOLUTION:-}$

Let l, b and h be the length, breadth and height of the shelter.

Given:

• l = 4m

• b = 3m

• h = 2.5m

Tarpaulin will be required for the top and four wall sides of the shelter.

Using formula, Area of tarpaulin required = 2(lh + bh)+lb

Put the values of l, b and h, we get

= [2(4 × 2.5 + 3 × 2.5) + 4 × 3] m²

= [2(10 + 7.5) + 12]m²

= 47 m²

• Therefore, 47 m² tarpaulin will be required