solve it... prove that
sec^2A(sec^2A-2)+1= tan^4A
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Sol'n:
LHS
= sec²A (sec²A - 2) + 1
= (tan²A + 1) (tan²A + 1 - 2) + 1
= (tan²A + 1) (tan²A - 1) + 1
= (tan²A)² - (1)² + 1
= tan⁴A - 1 + 1
= tan⁴A
= RHS
Hope it'll help...:)
LHS
= sec²A (sec²A - 2) + 1
= (tan²A + 1) (tan²A + 1 - 2) + 1
= (tan²A + 1) (tan²A - 1) + 1
= (tan²A)² - (1)² + 1
= tan⁴A - 1 + 1
= tan⁴A
= RHS
Hope it'll help...:)
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