Solve it (px-y) (py+x) =h²p
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Answer:
x = (h^2p+py^2)/y(p^2+p-1)
Step-by-step explanation:
(px-y)(py+x)=h^2p
p^2xy+pxy-py^2-xy=h^2p
p^2xy+pxy-xy=h^2p+py^2
xy(p^2+p-1)=h^2p+py^2
x=(h^2p+py^2)/y(p^2+p-1)
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