Math, asked by ashishsigh673, 11 months ago

Solve it (px-y) (py+x) =h²p​

Answers

Answered by ahana320
1

Answer:

x = (h^2p+py^2)/y(p^2+p-1)

Step-by-step explanation:

(px-y)(py+x)=h^2p

p^2xy+pxy-py^2-xy=h^2p

p^2xy+pxy-xy=h^2p+py^2

xy(p^2+p-1)=h^2p+py^2

x=(h^2p+py^2)/y(p^2+p-1)

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