Question

solve it...

Question from Trigonometry ​

Answer 1

SINCE ANGLE PSQ =90

PQ2 = PS2 +SQ2 (BY PYHTGORAS THEOREM )

PQ2 = 25

PQ = 5 CM

TAN THETA = PQ/RS

TAN THETA =5/9

Answer 2

In ∆PSQ, right-angled at S

Using Pythagoras Theorem

PS²+QS²=PQ²

$\sqrt{3^2+4^2}$=PQ

$\sqrt{9+16}$=PQ

$\sqrt{25}$=PQ

Therefore PQ=5

As we know

tan theeta = $\dfrac{Perpendicular}{Base}$

tan theeta = $\dfrac{5}{9}$

#$\underline{Be Brainly}$