Question

solve it (question in the attachment)​

Answer 1

Answer:

1299 is the right answer

Answer 2

Answer:

answer 1331

Step-by-step explanation:

consider

1/x+1/y+1/z=0,

taking lcm, we get

yz+xz+xy

   xyz        =0

shifting xyz to rhs we get

xy+yz+xz=0                  ---(Eq. 1)

now consider the formula

(x+y+z)^2=(x^2+y^2+z^2)+2xy+2yz+2xz

therefore

(11)^2=x^2+y^2+z^2+2(0)    [taking 2 common and appliying eq. 1]

121=x^2+y^2+z^2                       -----------(Eq.2)

now consider the proof,

x^3+y^3+z^3-3xyz=(x+y+z)(x^2+y^2+z^2-xy-yz-xz)

                             =(11)[121-(xy-yz-xz)]      --------(from given and Eq.2)

                             =(11)[121-(0)               ----------(Eq.1)

                             =(11)(121)

THEREFORE, X^3+Y^3+Z^3= 1331

Pls Pls Pls mark it as the brainliest it took em bout 1/2 hour to type

THANKS!!