Question

solve it quickly please​

Answer 1

Answer:

4

Explanation:

Integration of (2 t)dt limits 0 to 2

(2 tsquare / 2 ) limits 0 to 2

(tsquare) limits 0 to 2

(2)^2 - (0)^2

4

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Answer 2

$\huge \bf{ \underline{ \underline{{solution}}}} : -$

According to the question

$\implies \int\limits_{0}^{</u></strong><strong><u>2</u></strong><strong><u>} 2t \: .dt \\ \\ \implies \: {t}^{2} \\ \\ taking \: limits \: \\ \implies \: {</u></strong><strong><u>2</u></strong><strong><u>}^{2} - 0 = </u></strong><strong><u>4</u></strong><strong><u>$