Math, asked by karanpratapshaw, 1 year ago

solve it quickly please answer fast

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Answered by Swaroop1234
1

 \frac{1 -  \cos \: a }{1 +  \cos \: a }  =  \frac{(1 -  \cos \: a )(1 -  \cos\: a) }{(1 +  \cos\: a)(1 -  \cos \: a ) }  =  \frac{ {(1 -  \cos\: a) }^{2} }{1 -  { \cos }^{2} a}  \\  =  \frac{(1 -  { \cos \: a)}^{2}   }{ { \sin \: a }^{2} }  =  {( \frac{ 1 - \cos\: a }{ \sin\: a } )}^{2}  =   {( \frac{1}{ \sin \: a }  -  \frac{ \cos\: a}{ \sin\: a } )}^{2}  \\  =  {( cosec \: a -  \cot \: a)  }^{2}
Answer will be option (B).
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