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Answered by
1
Step-by-step explanation:
AB=CD(given)
adding BC both sides
AB+BC=CD+BC
AC=BD
(I) in ACE and DBF
AC=BD(prooved above)
CE=BF(given)
angleACE=angleDBF(given)
hence ACE is congruent to DBF (SAS)
(II) AE=DF(cpct)
hope this helps you
Answered by
1
Step-by-step explanation:
AB=CD given
AB+BC=AC
AND
CD+BC=BD
=AB+BC=BD (AB=CD)
AC=BD
<ACE=<DBF (GIVEN)
CE=BF (GIVEN)
SO,
∆ACE=∆DBF (BY SAS)
SO
AE=DF ( BY C.P.C.T)
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