solve it's ( 9+x) *(9-x) *17
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Answered by
6
Hola!!❤
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⏩( a + b ) ( a - b )= ( 9 + x ) ( 9 - x )
⏩a^2 - b^2 = 9^2 - x^2
➡(9^2 - x^2) * 17
➡(81 - x^2) * 17
➡ - 17x^2 + 1377
______________________________
______________________________
hope it helps ☺
✌be brainly
______________________________
______________________________
⏩( a + b ) ( a - b )= ( 9 + x ) ( 9 - x )
⏩a^2 - b^2 = 9^2 - x^2
➡(9^2 - x^2) * 17
➡(81 - x^2) * 17
➡ - 17x^2 + 1377
______________________________
______________________________
hope it helps ☺
✌be brainly
Answered by
0
Hey dear friend
(9+x)(9-x)*17
[By identity (a+b)(a-b)=(a²-b²)]
(9²-x²)17
(81-x²)17
1377-17x²
if it is equal to zero then,
1377-17x²=0
1377=17x²
1377/17=x²
81=x²
x=✓81
x= +9,-9
perfectly fine pure correct answer
hope it helps you mark me as brainliest and follow me
(9+x)(9-x)*17
[By identity (a+b)(a-b)=(a²-b²)]
(9²-x²)17
(81-x²)17
1377-17x²
if it is equal to zero then,
1377-17x²=0
1377=17x²
1377/17=x²
81=x²
x=✓81
x= +9,-9
perfectly fine pure correct answer
hope it helps you mark me as brainliest and follow me
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