Question

Solve it's urgent

options
a)1
b)2
c)3
d)1/2

don't spam​

Answer 1

Given:

ABCD is a parallelogram

BD is diagonal

AP and CQ are perpendiculars from the vertices A and C on diagonal BD

To Find:

The value of k

if $\frac{AP} {CQ} =k$

Solution:

In △APD and △CQB

∠APD=∠CQB(Each 90°)

AD=CB(opposite sides of parallelogram are always equal)

∠ADP=∠CBQ (Alternate angles)

So △APD ≅△CQB ( by AAS)

now, AP=CQ (by CPCT)

∴ $\frac{AP} {CQ} = \frac{AP} {AP}= 1$

→ (we can write AP in place of CQ as AP=CQ)

so the value of k = 1