solve it.......sin thita= cosec thita find thita=??
sabade72:
please
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Hey friend your answer,
Sin theta = Cosec theta
=>sin theta = 1/sin theta
=>Sin² theta =1
=>sin theta =1
=>theta =90°
Hope it helps you.
Sin theta = Cosec theta
=>sin theta = 1/sin theta
=>Sin² theta =1
=>sin theta =1
=>theta =90°
Hope it helps you.
Answered by
0
ANSWER....
![\sin(theta) = cosec(theta) \sin(theta) = cosec(theta)](https://tex.z-dn.net/?f=+%5Csin%28theta%29++%3D++cosec%28theta%29)
![\sin(theta) = \frac{1}{ \sin(theta) } \sin(theta) = \frac{1}{ \sin(theta) }](https://tex.z-dn.net/?f=+%5Csin%28theta%29++%3D++%5Cfrac%7B1%7D%7B+%5Csin%28theta%29+%7D+)
![\sin(theta) \times \sin(theta) = 1 \sin(theta) \times \sin(theta) = 1](https://tex.z-dn.net/?f=+%5Csin%28theta%29++%5Ctimes++%5Csin%28theta%29++%3D+1)
![{sin}^{2} theta = 1 {sin}^{2} theta = 1](https://tex.z-dn.net/?f=+%7Bsin%7D%5E%7B2%7D+theta+%3D+1)
![{sin}^{2} 90 degree = {1}^{2} {sin}^{2} 90 degree = {1}^{2}](https://tex.z-dn.net/?f=+%7Bsin%7D%5E%7B2%7D+90+degree+%3D+%7B1%7D%5E%7B2%7D+)
![{sin}^{2} 90degree = 1 {sin}^{2} 90degree = 1](https://tex.z-dn.net/?f=+%7Bsin%7D%5E%7B2%7D+90degree+%3D+1)
![therefore therefore](https://tex.z-dn.net/?f=therefore)
![theta = 90degree theta = 90degree](https://tex.z-dn.net/?f=theta+%3D+90degree)
![hope \: it \: helps hope \: it \: helps](https://tex.z-dn.net/?f=hope+%5C%3A+it+%5C%3A+helps)
![thanks thanks](https://tex.z-dn.net/?f=thanks)
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