Question

solve it solve it 2 and 3 question ​

Answer 1

$2. \: \: \: \: \frac{3 + 2 \sqrt{2} }{3 - 2 \sqrt{2} } = a - b \sqrt{2} \\ \frac{3 + 2 \sqrt{2} }{3 - 2 \sqrt{2} } \times \frac{3 + 2 \sqrt{2} }{3 + 2 \sqrt{2} } = a - b \sqrt{2} \\ \frac{9 + 6 \sqrt{2} + 6 \sqrt{2} + 8}{9 - 8} = a - b \sqrt{2} \\ 17 + 12 \sqrt{2} = a - b \sqrt{2} \\ a = 17 \: \: \: \: \: b = - 12 \\ \\ 3. \: \: \: \: x = \frac{2 - \sqrt{3} }{2 + \sqrt{3} } \\ y = \frac{2 + \sqrt{3} }{2 - \sqrt{3} } \\ x + y = \frac{2 - \sqrt{3} }{2 + \sqrt{3} } + \frac{2 + \sqrt{3} }{2 - \sqrt{3} } \\ = \frac{( {2 - \sqrt{3}) }^{2} + ( {2 + \sqrt{3} })^{2} }{4 - 3} \\ = 2(4 + 3) \\ = 14 \\ xy = 1 \\ now \: \: \: \: {x}^{2} + {y}^{2} = ( {x + y})^{2} - 2xy \\ = ( {14})^{2} - 2 \times 1 \\ = 196 - 2 \\ = 194$

Answer 2

Answer:

this is the answer of your 2nd.

hope it helps you!!

if yes then please mark my answer as brainliest!!!!

and the lines in your bio are really amazing bro!