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Step-by-step explanation:
In triangle ABC,
angle A+angle B+angle C=180°
(I will use /_ in place of angle)
180°- /_C= /_A + /_C
As /_C = 2×/_EAC
180°- 2×/_EAC = /_A + /_C
2(90- /_EAC) =/_A + /_C
As /_ADE = 90°
2(/_ADE - /_EAC) = /_A +/_C
Hence proved
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