solve it :-
tan x = - log cos x
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=d/dx log cosx
=1/-cosx[d/dx cosx]
=1/-cosx{-sinx}
=-sinx/-cosx
=tanx
Hence,prooved,L.H.S=R.H.S
=1/-cosx[d/dx cosx]
=1/-cosx{-sinx}
=-sinx/-cosx
=tanx
Hence,prooved,L.H.S=R.H.S
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