Question

Solve it :-


$\frac{3 \: - \: 5x}{3 \: - \: 4x} \: = \: \frac{ - 5x \: + \: 1}{5x \: - \: 1}$
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Answer 1

$\pink{hope \: it \: helps \: you..}$

Answer 2

Question :-

Solve :-

$\dfrac{3 \: - \: 5x}{3 \: - \: 4x} \: = \: \dfrac{ - 5x \: + \: 1}{5x \: - \: 1}$

Solution :-

$\qquad \quad {:} \longrightarrow \sf \boxed{\bf{\dfrac{3 \: - \: 5x}{3 \: - \: 4x} \: = \: \dfrac{ - 5x \: + \: 1}{5x \: - \: 1}}}$

$\qquad \quad {:} \longrightarrow \sf {\sf{\dfrac{3 \: - \: 5x}{3 \: - \: 4x} \: = \: \cancel\dfrac{ - 5x \: + \: 1}{5x \: - \: 1}}}$

$\qquad \quad {:} \longrightarrow \sf {\sf{\dfrac{3 \: - \: 5x}{3 \: - \: 4x} \: = \: \dfrac{ - 1}{1}}}$

Now, Using Cross Multiplaction.

$\qquad \quad {:} \longrightarrow \sf {\sf{1(3 - 5x) \: = \: - 1(3 - 4x)}}$

$\qquad \quad {:} \longrightarrow \sf {\sf{3 \: - \: 5x\: = \: - 3 \: + \: 4x}}$

$\qquad \quad {:} \longrightarrow \sf {\sf{3 \: + \: 3\: = \: 5x \: + \: 4x}}$

$\qquad \quad {:} \longrightarrow \sf {\sf{6\: = \: 9x}}$

$\qquad \quad {:} \longrightarrow \sf {\sf{ \dfrac{6}{9} \: = \: x}}$

$\qquad \quad {:} \longrightarrow \sf {\sf{ \cancel\dfrac{6}{9} \: = \: x}}$

$\qquad \quad {:} \longrightarrow \sf \boxed{\bf{ \dfrac{2}{3} \: = \: x}}$

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More For Knowledge :-

$\underbrace\red{\boxed{ \sf \green{ Rules \: to \:Solve \: a \: Equation}}}$

• Rule 1 :- Same quantity ( number ) can be added to both side of an equation without changing the equality.
• Rule 2 :- Same quantity can be subtracted from both sides of an equation without changing the quality
• Rule 3 :- Both sides of an equation may be multiplied by the same non zero number without changing the quality.
• Rule 4 :- Both sides of an equation may be divided by the same non zero number without changing the quality.

$\begin{gathered}\\ \\\end{gathered}$

Note :-

• It should be noted that some complicated equation can be solved by using two or more of these rules together.

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