Question

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Answer 1

21.99cm² ≈ 22cm²

Step-by-step explanation:

Let outer diameter be D = 6.4cm

Inner diameter is d = 3.6cm

Area of the washer will be = π(D² - d²)/4

$\pi( \frac{ {d1}^{2} - {d2}^{2} }{4} ) \\ = \frac{\pi}{4} (d1 \: + \: d2) \times (d1 \: - \: d2) \\ = \frac{\pi}{4} (6.4 \: + \: 3.6) \times (6.4 \: - \: 3.6) \\ = \frac{\pi}{4} \times 10 \times 2.8 \\ = 21.99 {cm}^{2}$

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Answer 2

Answer :- $22 Cm^2$

Solution :-

Since, Diameter of the tap = 6.4 Cm.

Therefore, Radius of the tap (R)= 3.2 Cm.

And, Diameter of the hole in the tap = 3.6 Cm.

Radius of the hole (r) = 1.8 Cm.

Area of the washer = Area of the tap - Area of the hole in it.

$\implies πR^2 - πr^2$

$\implies π(3.2)^2 - π(1.8)^2$

$\implies π (10.24 - 3.24)$

$\implies π × 7$

$\implies 22.$

Hence, The Area of the washer is $\boxed {22\ Cm^2}$.

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