Question

solve it !

Thanks :D

Answer 1

Hi there !!

Refer to the attachment for the method !

Answer 2

➡HERE IS YOUR ANSWER⬇

$\frac{ {m}^{4} \times {n}^{4} \times ( {mn})^{ - 4} }{( {m}^{3} \times {n}^{ - 3} )} \\ \\ = \frac{ {m}^{4} \times {n}^{4} \times {m}^{ - 4} \times {n}^{ - 4} }{ {m}^{3} \times {n}^{ - 3} } \\ \\ (since \: \: ( {ab})^{k} = {a}^{k} \times {b}^{k} )\\ \\ = \frac{( {m}^{4} \times {m}^{ - 4}) \times ( {n}^{4} \times {n}^{ - 4} ) }{ {m}^{3} \times {n}^{ - 3} } \\ \\ = \frac{ {m}^{(4 - 4)} \times {n}^{(4 - 4)} }{ {m}^{3} \times {n}^{ - 3} } \\ \\ (since \: \: {a}^{k} \times {a }^{ - k} = {a}^{k - k} ) \\ \\ = \frac{ {m}^{0} \times {n}^{0} }{ {m}^{3} \times {n}^{ - 3} } \\ \\ = \frac{1 \times 1}{ {m}^{3} \times {n}^{ - 3} } \: \: (since \: \: {a}^{0} = 1) \\ \\ = \frac{1}{ {m}^{3} \times {n}^{ - 3} } \\ \\ = \frac{ {n}^{3} }{ {m}^{3} } \: \: (since \: \: \frac{1}{ {a}^{ - k} } = {a}^{k} ) \\ \\ = ( { \frac{n}{m} })^{3} \\ \\ (since \: \: ( { \frac{a}{b} })^{k} = \frac{ {a}^{k} }{ {b}^{k} } )$

⬆HOPE THIS HELPS YOU⬅