Question

solve it. the value of (3-⁵÷3-⁷)÷3-²​

Answer 1

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Answer 2

Answer:

The value of ((3)⁻⁵ ÷(3)⁻⁷) ÷ (3)⁻² = 81

Step-by-step explanation:

Given that((3)⁻⁵ ÷(3)⁻⁷) ÷ (3)⁻²

We have to solve the expression

((3)⁻⁵ ÷(3)⁻⁷) ÷ (3)⁻²

We know that $\frac{a^{m} }{a^{n} } = a^{m-n}$

first we find the value of ((3)⁻⁵ ÷(3)⁻⁷)

$\frac{3^{-5} }{3^{-7} } =3^{-5+7} =3^{2} =9$

Now ((3)⁻⁵ ÷(3)⁻⁷) ÷ (3)⁻²

(3)²÷(3)⁻² = $\frac{3^{2} }{3^{-2} } =3^{2+2} =3^{4} =81$.

3⁴ = 3×3×3×3 = 81

Therefore, ((3)⁻⁵ ÷(3)⁻⁷) ÷ (3)⁻² = 81