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According to the question (A+B)'s one day work= 1/72 (B+C)'s one day work=1/120 (C+A)'s one day work=1/90 On Adding all the 3 2(A+B+C)'s one day work=1/72+1/120+1/90 =5+3+4/360= 1/30 Therefore (A+B+C)'s one day work= 1/60 Therefore A,B,C can together finish the whole work in 60 days Hence the option is B
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(A+B)'s one day work= 1/72
(B+C)'s one day work=1/120
(C+A)'s one day work=1/90
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