solve it trigonometry question
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bro ye question aise he hoyega, Mai Abhi Ghar se bahar hu is vajah se shayad ye question Galt ho jaaye but method yahi hoga karne ka.
ho sakega to Mai Ghar jàakar ise edit kardunga..
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Step-by-step explanation:
given 1-sin^2a=tan^2
divide by cos^2a
then sec^a-tan^2a-sin^2a
rhs,
=1+cos^2a/cos^2
=tan^2a+sin^2a+cos^2a/cos^2a
=sin^2a+cos^2asin^2a+cos^4a/1
=sin^a+cos^2a(sin^2a+cos^2a)
=sin^2a+cos^a
=1
=1 also can be written as sec^2a-tan^2
then sin^2=1+cos^2a/cos^2a
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