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let the time taken by I tap to fill the cistern completely = x minutes.
thus, let the time taken by II tap to fill the cistern = (x + 5) minutes.
work done by tap I (in 1 min) = 1/x
work done by tap II (in 1 min) = 1/(x+5)
work don by tap I +work done by tap II in 1 minute = cistern filled in one minute = 1/6
thus the equation is 1/x + 1/(x+5) = 1/6.
6(2x+5) = x2 + 5x
12x + 30= x2 + 5x
x2 -7x -30= 0.
x2 +3x -10x -30 = 0.
x(x+3) -10(x+3) = 0.
time cannot be negative.
thus , x= 10.
thus, time taken by tap I = 10 minutes.
time taken by tap II = x+5 = 15 minutes.
HOPE THIS HELPS YOU.
PLEASE MARK THE BRAINLIEST...
thus, let the time taken by II tap to fill the cistern = (x + 5) minutes.
work done by tap I (in 1 min) = 1/x
work done by tap II (in 1 min) = 1/(x+5)
work don by tap I +work done by tap II in 1 minute = cistern filled in one minute = 1/6
thus the equation is 1/x + 1/(x+5) = 1/6.
6(2x+5) = x2 + 5x
12x + 30= x2 + 5x
x2 -7x -30= 0.
x2 +3x -10x -30 = 0.
x(x+3) -10(x+3) = 0.
time cannot be negative.
thus , x= 10.
thus, time taken by tap I = 10 minutes.
time taken by tap II = x+5 = 15 minutes.
HOPE THIS HELPS YOU.
PLEASE MARK THE BRAINLIEST...
BilluGautam:
thanks ritu jain...u r so genius
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