Question

solve it using cross multiplication method


please solve it and please don't spam I am giving you 15 points for that​

Answer 1

Given Equations:-

• 8x + 13y - 29 = 0
• 12x - 7y - 17 = 0

To Find:-

• The vale of x and y

Method to be used:-

• Cross-multiplication method.

Befor solving:-

We need to find values of $\sf{a_1,\:a_2,\:b_1,\:b_2,\:c_1,\:c_2}$

Here in these equations:-

$\sf{a_1 = Coefficient\:of\:x\:of\:1st\:equation= 8}$

$\sf{a_2 = Coefficient\:of\:x\:of\:2nd\:equation = 12}$

$\sf{b_1 = Coefficient\:of\:y\:of\:1st\:equation = 13}$

$\sf{b_2 = Ciefficienf\:of\:y\:of\:2nd\:equation = -7}$

$\sf{c_1 = Constant\:term\:of\:1st\:equation = -29}$

$\sf{c_2 = Constant\:term\:of\:2nd\:equation = -17}$

Solution:-

We know,

That for cross-multiplication method and equation is represented as:-

$\sf{\dfrac{x}{b_1c_2 - b_2c_2} = \dfrac{y}{c_1a_2 - c_2a_1} = \dfrac{1}{a_1b_2 - a_2b_1}}$

Substituting the values:-

$\sf{\dfrac{x}{(13)(-17)-(-7)(-29)} = \dfrac{y}{(-29)(12)-(-17)(8)} = \dfrac{1}{(8)(-7)-(13)(12)}}$

= $\sf{\dfrac{x}{-221 - 203} = \dfrac{y}{-348+136} = \dfrac{1}{-56-156}}$

= $\sf{\dfrac{x}{-424} = \dfrac{y}{-212} = \dfrac{1}{-212}}$

Now,

$\sf{\dfrac{x}{-424} = \dfrac{1}{-212}}$

= $\sf{x = \dfrac{-424}{-212}}$

=> $\sf{x = 2}$

And,

$\sf{\dfrac{y}{-212} = \dfrac{1}{-212}}$

= $\sf{y = \dfrac{-212}{-212}}$

=> $\sf{y = 1}$

Therefore, value of:-

• x = 2
• y = 1

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Answer 2

Answer:

refer the attachment

hope it helps you