Question

solve it using identity please help me my friends ​

Answer 1

Answer:

$(x + y) ^{3} = x {}^{3} + y {}^{3} + 3x {}^{2} y + 3y {}^{2} x$

by using above identity,

$( \frac{2}{3} x + \frac{3}{4}y) {}^{3}$

=(2/3x)^3+(3/4y)^3+3(2/3x)^2×3/4y+3×(3/4y)^2×2/3x

=

$\frac{8}{27}x {}^{3} + \frac{27}{64} y {}^{3} + x {}^{2} y + \\ \frac{9}{8} x {}^{2}$

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