Question

solve it using middle term splitting
$100 {x}^{2} - 20x + 1 = 0$
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Answer 1

Answer:

100x^2- 10x+10x+1

=10x(10x-1)-1(10x-1)

=(10x-1)(10x-1)

Answer 2

$\huge\sf\underline{Solution}$

100x² - 20x + 1

= 100x² - (10x + 10x) + 1

= 100x² - 10x - 10x + 1

= 10x (10x - 1) - 1 (10x - 1)

= (10x - 1) (10x - 1)

Hence, Either (10x - 1) = 0 or (10x - 1) = 0. Since both of the linear polynomial are the same,

Therefore, Zero of the polynomial (10x - 1) :-

=> 10x - 1 = 0

=> 10x = 1

=> x = 1/10

Hence the zero of the polynomial is 1/10.