Question

solve it..value of x

Answer 1

i hope it can help ....

Answer 2

Here is your answer

$2 {}^{2x} - 2 {}^{x + 3} = - 2 {}^{4} \\ let \: 2 {}^{x} = y \\ y {}^{2} - 8y = - 16 \\ y {}^{2} - 8y + 16 = 0 \\ y {}^{2} - 4y - 4y + 16 = 0 \\ y(y - 4) - 4(y - 4) = 0 \\ (y - 4)(y - 4) = 0 \\ y = 4 \\ put \: the \: value \\ 2 {}^{x} = 4 \\ 2 {}^{x} = 2 {}^{2} \\ x = 2 \: \: \: \: answer$
Hope it helps you