Math, asked by Yacika, 1 year ago

Solve it.. very urgent

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Answered by lohithanaidu
3
Given ΔABC is equilateral and AD⊥BC. That is AD bisects BC at 'D'.
It is given that the length of the side BC is 'x' units.⇒AB=BC=AC=x units.
Here, ΔABD is right angled triangle.
So,by Pythagoras theorem,
AB²=AD²+BD² 
⇒x²=AD²+(x/2)²  [∵BC is bisected at D]
⇒AD²=x²-x²/4
⇒AD²=3x²/4
⇒AD=[(√3)x]/2.

lohithanaidu: Thanku.. :)
Yacika: Well come
Answered by suraniparvin
0
See the attach file for ansu
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