Solve it with algebraic identity
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x^2-(y+1)^2=(x+y+1) (x-y-1)
imagenius:
Thanks kriti and next time when u answer ...do it with full procedure:)
Answered by
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Here is your answer buddy====;;::::!
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Ans : (x-y-1)(x+y+1)
By using a2−b2=(a−b)(a+b)a2−b2=(a−b)(a+b)
The only thing which is different from this is you must have to arrange it into this form. So below are the steps.
x2−(y2+2y+1)x2−(y2+2y+1) ==>we take - commonx2−(y+1)2==>(a2+2ab+b2)=(a+b)2x2−(y+1)2==>(a2+2ab+b2)=(a+b)2(x−(y+1))(x+(y+1))(x−(y+1))(x+(y+1))=>applying the main rule a2−b2=(a−b)(a+b)a2−b2=(a−b)(a+b)(x−y−1)(x+y+1)(x−y−1)(x+y+1)=>simplyfying the answer
i write square as2
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Ans : (x-y-1)(x+y+1)
By using a2−b2=(a−b)(a+b)a2−b2=(a−b)(a+b)
The only thing which is different from this is you must have to arrange it into this form. So below are the steps.
x2−(y2+2y+1)x2−(y2+2y+1) ==>we take - commonx2−(y+1)2==>(a2+2ab+b2)=(a+b)2x2−(y+1)2==>(a2+2ab+b2)=(a+b)2(x−(y+1))(x+(y+1))(x−(y+1))(x+(y+1))=>applying the main rule a2−b2=(a−b)(a+b)a2−b2=(a−b)(a+b)(x−y−1)(x+y+1)(x−y−1)(x+y+1)=>simplyfying the answer
i write square as2
u got????
yes
i understood it
Hey
Can u also send a pic of this procedure if possible?
How can i send brainly doesn't allow
it allows to edit
But in editing not to put a pic.
i have asked one question plz answer it
Okk
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