Question

Solve it with algebraic identity

Answer 1

x^2-(y+1)^2=(x+y+1) (x-y-1)

Answer 2

Here is your answer buddy====;;::::!

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Ans : (x-y-1)(x+y+1)

By using a2−b2=(a−b)(a+b)a2−b2=(a−b)(a+b)

The only thing which is different from this is you must have to arrange it into this form. So below are the steps.

x2−(y2+2y+1)x2−(y2+2y+1) ==>we take - commonx2−(y+1)2==>(a2+2ab+b2)=(a+b)2x2−(y+1)2==>(a2+2ab+b2)=(a+b)2(x−(y+1))(x+(y+1))(x−(y+1))(x+(y+1))=>applying the main rule a2−b2=(a−b)(a+b)a2−b2=(a−b)(a+b)(x−y−1)(x+y+1)(x−y−1)(x+y+1)=>simplyfying the answer



i write square as2