Math, asked by Nidhi0000, 10 months ago

solve it

with explaination

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Answers

Answered by StarrySoul
29

Solution :

In the figure we can have a look at 3 different species that is • Tortoise (Shown in the first row) • Crab (Shown in the second row) and • Octopus (Shown in the third row)

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Let's assume the value of Tortoise be x, Crab be y and Octopus be z

Starting From the First Row :

 \longrightarrow  \sf \: x + x + x = 30

 \longrightarrow  \sf \: 3x = 30

 \longrightarrow  \sf \: x =   \cancel\dfrac{30}{3}

 \longrightarrow  \sf \: x =   \large\boxed{ \sf \: 10}

Coming to the Second Row :

 \longrightarrow  \sf \: x + y + y = 20

 \longrightarrow  \sf \: 10 + y  + y= 20

 \longrightarrow  \sf \: 10 + 2y = 20

 \longrightarrow  \sf \:  2y = 20 - 10

 \longrightarrow  \sf \:  2y = 10

 \longrightarrow  \sf \:  y =   \cancel\dfrac{10}{2}

 \longrightarrow  \sf \: y =   \large\boxed{ \sf \: 5}

Coming to the Third Row :

We've taken value of Octopus as z but in this row there are 2 Octopuses. So, We'll take it as 2z

 \longrightarrow  \sf \: z + z + y  = 25

 \longrightarrow  \sf \: 2z +  5  = 25

 \longrightarrow  \sf \: 2z  = 25 - 5

 \longrightarrow  \sf \: 2z  = 20

 \longrightarrow  \sf \: z =   \cancel\dfrac{20}{2}

 \longrightarrow  \sf \: z=   \large\boxed{ \sf \: 10}

Now, We've to find the value of Tortoise + Crab × Octopus

 \sf \longrightarrow x + y \times z

 \sf \longrightarrow 10 + 5\times 10

 \sf \longrightarrow 10+ 50

 \bigstar \sf  \:  \large\boxed{  \sf60}

Hence,Required Value is 60

Answered by RvChaudharY50
21

Answer :--

Lets Assume That :-

Tortoise = x

→ Crab = y

→ Octopus = z.

Than, we Have Given That :-

x + x + x = 30

→ 3x = 30

Dividing both sides by 3 ,

x = 10 --------- Equation (1).

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Now, we have :-

x + y + y = 20

→ x + 2y = 20

Putting value from Equation (1) here,

10 + 2y = 20

→ 2y = 20 - 10

→ 2y = 10

Dividing both sides by 2,

y = 5 ----------- Equation (2)

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In Last , we have Given :-

2*Z + y = 25

Putting value from Equation (2),

2z = 25 - 5

→ 2z = 20

Dividing both sides by 2,

z = 10 -------------- Equation (3).

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Now, we Have To Find :-

x + y * z

Putting values From Equation (1), (2) & (3),

10 + 5 * 10

→ 10 + 50

60 (Ans).

Hence, ( Tortoise + Crab + Octopus ) is 60.

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