solve it with explainations 12 no
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urgent i need the ans quickly
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Sol : The answer is option ( d ) √xy = √x √y
Explanation : For option ( a ),
√x - √y = √( x - y )
By squaring both sides ,
( √x - √y )² = √( x - y )²
( √x )² + ( √y )² - 2 * √x * √y = x - y
x + y - 2 * √x * √y = x - y
x + y - x + y = 2 * √x * √y
2 y = 2 * √x * √y
y = √ x * √y
y / √y = √x
√y = √x
y = √x²
y = x.
But it is given that y < x.So, it is incorrect.
For option ( b ),
√x + √x = √( 2x )
By taking √x common in L.H.S ,
√x( 1 + 1 ) = √( 2 x )
√x ( 2 ) = √( 2 x )
{ √x ( 2 ) }² = 2 x
4 x = 2 x
4 x - 2 x = 0
2 x = 0
x = 0 / 2
x = 0.
But it is given that 0 < x , hence it is also incorrect .
For option ( c ),
x√y = y√x
x = y√x / √y
x = √ y . √x
x / √x = √y
√x = √y
x = (√y)²
x = y.
But it is given that y < x .So, it is not possible.
For option ( d ),
√( xy ) = √x * √y
√( xy ) = x^ ( 1/2) * y^( 1/2) { √a = a^(1/2) }
√( x y ) = ( x y )^( 1/2 ) { m^a * n^a = ( mn )^a }
√(xy ) = √(xy) { a^(1/2) = √a }
xy = xy
So, it is possible .
___________________________________________
Explanation : For option ( a ),
√x - √y = √( x - y )
By squaring both sides ,
( √x - √y )² = √( x - y )²
( √x )² + ( √y )² - 2 * √x * √y = x - y
x + y - 2 * √x * √y = x - y
x + y - x + y = 2 * √x * √y
2 y = 2 * √x * √y
y = √ x * √y
y / √y = √x
√y = √x
y = √x²
y = x.
But it is given that y < x.So, it is incorrect.
For option ( b ),
√x + √x = √( 2x )
By taking √x common in L.H.S ,
√x( 1 + 1 ) = √( 2 x )
√x ( 2 ) = √( 2 x )
{ √x ( 2 ) }² = 2 x
4 x = 2 x
4 x - 2 x = 0
2 x = 0
x = 0 / 2
x = 0.
But it is given that 0 < x , hence it is also incorrect .
For option ( c ),
x√y = y√x
x = y√x / √y
x = √ y . √x
x / √x = √y
√x = √y
x = (√y)²
x = y.
But it is given that y < x .So, it is not possible.
For option ( d ),
√( xy ) = √x * √y
√( xy ) = x^ ( 1/2) * y^( 1/2) { √a = a^(1/2) }
√( x y ) = ( x y )^( 1/2 ) { m^a * n^a = ( mn )^a }
√(xy ) = √(xy) { a^(1/2) = √a }
xy = xy
So, it is possible .
___________________________________________
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