Math, asked by Anonymous, 11 months ago

solve it with full explanation..​

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Answered by Anonymous
5

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 {3}^{2x + 1}  \div 9 = 27

 {3}^{2x + 1}  \div  {3}^{2}  =  {3}^{3}

 {3}^{2x + 1 - 2}  =  {3}^{3}

 {3}^{2x - 1}  =  {3}^{3}

Bases are same so we equate powers

2x - 1 = 3

2x = 3 + 1

x =  \frac{4}{2}

x = 2

Answered by rekhasingh86501
0

Answer:

2

Step-by-step explanation:

In second step-

Convert every number to it's exponent form...

In third step-

Divide with the exponent law that states -

If the base is same then and it is the case of division then take the same base and subtract the powers...

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