Question

solve it .

with process. jisko answer dena he wo de . jisko nahi dena wo mat dena ..

solve it ..eska answer he rs. 31,762.50​

Answer 1

Solution

Given:-

• Radius of circular park = 56 m
• 3.5 m wide road arround the circular park
• cost of construction of per square meter = ₹ 25

Find :-

• Total cost of construction

Explanation

Using Formula

$\dag\boxed{\underline{\tt{\orange{\:Area_{circular\:park}\:=\:\pi\:r^2}}}}$

Where,

• r = radii of circular park
• π = 22/7

Keep above Values,

==> Area of circular park = 22/7 × (56)²

==> Area of circular park = 22/7 × 56 × 56

==> Area of circular park = 22 × 56 × 8

==> Area of circular park = 176 × 56

==> Area of circular park = 9,856 m2

Here, road construct around the circular park whose radii is 3.5 m

Then,

Radius of whole circle ,

==> Radius of whole circle= 56 + 3.5

==> Radius of whole circle= 59.5 m

Now, Calculate Area of whole circle

==> Area of whole circle = 22/7 × (59.5)²

==> Area of whole circle = 22/7 × 59.5 × 59.5

==> Area of whole circle = 22 × 59.5 × 8.5

==> Area of whole circle = 11,126.5 m²

Now, Calculate Area of circular road.

==> Area of circular road = Area of whole circle - Area of circular park

==> Area of circular road = 11,126.5 - 9,856

==> Area of circular road = 1270.5 m²

________________________

Now, Calculate cost of total construction

∵cost of construction of 1 m² road = ₹25

•°• Total cost of construction of 1270.5 m² = 25 × 1270.5

•°• Total cost of construction of 1270.5 m² = ₹ 31,762.5

Hence

• Total cost of construction of circular road = ₹ 31,762.5

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