Question

solve it................... with proper solution..................

Answer 1

$a + \frac{1}{a + 2} = 0 \\ a = - \frac{1}{a + 2} \\ a + 2 = \frac{ - 1}{a}$
put this value in eq
$= ( { \frac{ - 1}{a} )}^{3} + \frac{1}{ ({ \frac{ - 1}{a} )}^{3} } \\ = \frac{ - 1}{ {a}^{3} } - {a}^{3} \\ = \frac{ - (1 + {a}^{6} )}{ {a}^{3} }$