Question

solve it with step by step explanation......​

Answer 1

Hiiii. ....friend ,

Here is ur answer,

$= > \frac{3 + 2i}{2 - 3i} + \frac{3 - 2i}{2 + 3i}$

$= > \frac{(3 + 2i)(2 + 3i) + (3 - 2i)(2 - 3i)}{(2 - 3i)(2 + 3i)}$

$= > \frac{6 + 4i + 9i - 6 + 6 - 4i - 9i - 6}{ {2}^{2} + { 3}^{2} }$

=> 0.

:-) Hope it helps u.