Question

solve it with steps please

Answer 1

triangles PXZ and PXQ
< P = < P
<PXQ = <PZX
so, triangle PXZ similar to PXQ
similarly triangles PXZ and ZXQ are similar

so, from these we came to know that,
triangles PXQ is similar to ZXQ
By BPT,
XZ/PZ = ZQ/XZ
by cross multipying,
XZ^2 = PZ.ZQ