Question

solve it with steps...

$a = {a}^{2} + 1 \\ then \:find \: the \: vlue \: of \: \: \\ {a}^{12} + {a}^{6} + 1$

Answer 1

a² +1 =a
=>a^6=(a²+1)^6
=>a^12+6a^10+15a^8+15a^6+6a^4+1=a^6
Now,
a^12+a^6+1=2a^12+6a^10+15a^8+15a^6+6a^4+2