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Answer:
x=40° and y=78°
Step-by-step explanation:
given AB//CD
given ∠APQ = 40°
given ∠PRD = 118°
let ∠PRQ = z
so, ∠PRD + ∠PRQ = 180° ( linear pair)
118° + z = 180°
z = 62°
and, ∠APQ = x = 40° (alternate interior angles)
now, x + y + z = 180° (sum of angles in a triangle)
40° + y + 62° = 180°
102° + y = 180°
y = 180° - 102°
y = 78°
hence, x = 40°
y = 78°
hope this is helpful,
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