Question

Solve it . wrong one will be report. ​

Answer 1

Let ,

Girl face = x

Boy face = y

Condition 1 :

➠ $\sf 2(x)- \dfrac{4}{ (y) } =10$

➠ $\sf \dfrac{2(x)(y)-4}{(y)}=10$

➠ $\sf 2xy - 4 = 10y$

➠ $\sf 2xy - 10y = 4\ \dashrightarrow (1)$

Condition 2 :

➠ $\sf 2(x) + \dfrac{2}{(y)} = 4$

➠ $\sf \dfrac{ 2(x)(y) + 2 }{(y)} = 4$

➠ $\sf 2xy + 2 = 4y$

➠ $\sf 2xy - 4y = -2\ \dashrightarrow (2)$

On sub. eq (2) from eq (1) ,

➠ 2xy - 10y - ( 2xy - 4y ) = 4 - (-2)

➠ 2xy - 10y - 2xy + 4y = 6

➠ - 6y = 6

➠ y = - 1  $\pink{\bigstar}$

On sub. 'y' value in eq (1) ,

➠ 2x(-1) - 10(-1) = 4

➠ - 2x + 10 = 4

➠ 10 - 4 = 2x

➠ 2x = 6

➠ x = 3  $\green{\bigstar}$

Our required ,

Condition 3 :

➠ x - y

➠ (3) - (-1)

➠ 3 + 1

➠ 4  $\purple{\bigstar}$

Answer 2

Answer:

Hope it's help you dear..