Question

Solve it
x+1/3 - x-6/2 = x/2​

Answer 1

Answer:

Value of x = $\bf{-5\dfrac{1}{3}}$

Step-by-step explanation:

Given :

$\bf{x+\dfrac{1}{3}-x-\dfrac{6}{2}=\dfrac{x}{2}}$

To find :

The value of x

Solution :

$:\implies\bf{x+\dfrac{1}{3}-x-\dfrac{6}{2}=\dfrac{x}{2}}$

$:\implies\bf{\dfrac{1}{3}-\dfrac{6}{2}=(\dfrac{x}{2}+\dfrac{x}{1})-\dfrac{x}{1}}$

L.C.M. of 3 and 2 is 6 .

$:\implies\bf{\dfrac{2-18}{6}=(\dfrac{x+2x}{2})-\dfrac{x}{1}}$

$:\implies\bf{\dfrac{-16}{6}=\dfrac{3x}{2}-\dfrac{x}{1}}$

$:\implies\bf{\dfrac{-16}{6}=\dfrac{3x-2x}{2}}$

$:\implies\bf{\dfrac{-16}{6}=\dfrac{x}{2}}$

Now , cross multiply the number

$:\implies\bf{\dfrac{-16}{\cancel{6}}\times\cancel{2}=x}$

$:\implies\bf{\dfrac{-16}{3}=x}$

Now , make the improper fraction into mixed fraction.

$:\implies\bf{-5\dfrac{1}{3}=x}$

So , the value of x is $\bf{-5\dfrac{1}{3}}$

Answer 2

Answer:

$= x + \frac{1}{3} - x - \frac{6}{2} = \frac{x}{2} . \\ = x + ( - x) - \frac{x}{2} = - \frac{1}{3} + \frac{6}{2} . \\ = x - x - \frac{x}{2} = \frac{ - 2 + 18}{6} . \\ = 0 - \frac{x}{2 } = \frac{16}{6} . \\ = - \frac{x}{2} = \frac{16}{6} . \\ = - 6x = 32. \\ = x = \frac{32}{ - 6} . \\ = x = \frac{ - 16}{3} .$