solve it x^2+x-2 is equal to ?
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Answered by
1
hi
x² + x - 2
= x² + ( 2 - 1 )x - 2
= x² + 2x - x - 2
= x( x + 2 )-1( x + 2 )
= ( x + 2 ) ( x - 1 )
either
x - 1 = 0 or x + 2 = 0
=> x = 1 or x = - 2
_______________________________
x² + x - 2
= x² + ( 2 - 1 )x - 2
= x² + 2x - x - 2
= x( x + 2 )-1( x + 2 )
= ( x + 2 ) ( x - 1 )
either
x - 1 = 0 or x + 2 = 0
=> x = 1 or x = - 2
_______________________________
Answered by
1
Hello !!!!!!
=========================================================
x² + x - 2
=> x² + ( 2 - 1 ) x - 2
=> x² + 2x - x - 2
=> x ( x + 2 ) - 1 ( x + 2 )
=> ( x + 2 ) ( x - 1 )
=> x = 1 or x = -2
=========================================================
x² + x - 2
=> x² + ( 2 - 1 ) x - 2
=> x² + 2x - x - 2
=> x ( x + 2 ) - 1 ( x + 2 )
=> ( x + 2 ) ( x - 1 )
=> x = 1 or x = -2
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