Math, asked by ganeshpp70, 8 months ago

Solve it :-

(x+2y+4z)^2

Answers

Answered by kusumakusuma154
5

(x + 2y + 4z) ²

x + 2y² + 4z²

= x + 4* y² + 16 * z²

Answered by Anonymous
52

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(x+2y+4z)^2

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Used formula-

(a+b+c)² = a² + b² + c² + 2 [ab + bc + ca]

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solution-

(x+2y+4z)^2

[x + (-2y) + 4z]²

x² + (-2y)² + 4z² + 2[(-2xy) + (-8zy) + 4zx]

x² + 4y² + 16z² + 2[-2xy -8zy + 4zx]

x² + 4y² + 16z² -4xy -16zy + 8zx

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Answer-

x² + 4y² + 16z² -4xy -16zy + 8zx

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