Solve it:x^4-5x^2+6=0
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Solve this by an easy and common method. I.e. Middle term splitting.
Let x2=y
Now , x4—5x2+6=0
y2—5y+6=0
y2—2y—3y+6=0
y(y−2)−3(y−2)=0
(y−3)(y−2)=0
Therefore, y=3 or y=2
Previously we have assume that x2=y
Therefore, x2=3orx2=2
x=+√3orx=+√2
Therefore, there are 4 solutions of this equation
I.E. [math]x=+√3;-√3;+√2;-√2[/math]
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